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#constant speed

10 public questions tagged with this topic.

Displacement Current and Ampere-Maxwell Law

What property of electromagnetic waves explains their ability to travel at the same speed in vacuum regardless of their

**Ampere-Maxwell law** ∮ B·dl = μ₀(I_c + ε₀ dΦ_E/dt) generalizes Ampere's law, displacement current arises from time-varying electric field, source of magnetic field like conduction current. For rate of change of flux 2×10¹¹ V·m/s, I_d = ε₀×2×10¹¹ =8.85×10⁻¹²×2×10¹¹=1.77 A. The speed of electromagnetic waves in vacuum depends only on the permittivity ( ε₀ ) and permeability ( μ₀ ) of free space, given by c = (1/√(μ₀ ε₀)) , which is constant. Using c = fλ, E₀/B₀ = c, I_d = ε₀ dΦ_E/dt, and spectrum classification λ = c/f, evaluation yields Dependence on permittivity and permeability, illustratin

Ref: NCERT > Physics Book > Electromagnetic Waves > Displacement Current and Ampere-Maxwell Law

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Uniform Acceleration and Graphical Analysis

A car accelerates from 10m/s at 1.5m/s2 for 6s, then moves at constant speed for 4s. What is the average speed over the

Phase 1: v=10+1.5⋅6=19m/s, x1=10⋅6+12⋅1.5⋅(6)2=60+27=87m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 17 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis

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Distance, Displacement and Velocity-Time Relations

A cyclist moves at a constant speed of 12m/s for 30s. What is the distance covered?

For constant speed, distance x=vt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 360 m as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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Distance, Displacement and Velocity-Time Relations

A train moves with a constant speed of 108km/h for 2min. What is the distance traveled?

Convert speed: 108km/h=108⋅10003600=30m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 30 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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Free Fall and Vertical Motion

A rocket accelerates from rest at 6m/s2 for 5s, then moves at constant speed for 3s. What is the total distance covered?

Phase 1: v=6⋅5=30m/s, x1=12⋅6⋅(5)2=75m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 165 m as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Free Fall and Vertical Motion

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Kinematic Equations and Uniformly Accelerated Motion

A cyclist moves with a constant speed of 5m/s for 20s. What is the distance covered?

For constant speed, distance x=vt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 100 m as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A car accelerates from 12m/s at 1.5m/s2 for 4s, then moves at constant speed for 5s. What is the average speed over the

Phase 1: v=12+1.5⋅4=18m/s, x1=12⋅4+12⋅1.5⋅(4)2=48+12=60m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 17 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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