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Pav = FA, F = mg = 70×9.8 = 686N. Total area A = 2×16×10−4 = 3.2×10−3m2. Pav = 6863.2×10−3 = 2.14375×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.14 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 60×10 = 600N. Total area A = 2×15×10−4 = 3×10−3m2. Pav = 6003×10−3 = 2×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
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