A 900kg satellite orbits Earth at 14RE from the center. What is its total energy? (ME\=6×1024kg,RE\=6.4×106m,G\=6.67×10−
E = −GMEm2r. r = 14RE = 8.96×107m. E = −6.67×10−11×6×1024×9002×8.96×107. E = −3.602×10171.792×108≈−2.01×109J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -2.0 × 10⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.