We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy2 public questions tagged with this topic.
T2 = k(RE+h)3, where k = 4π2GME. For h = 0, T0 = 84min, T02 = kRE3. For h = RE, r = 2RE, T2 = k(2RE)3 = 8kRE3. T = 8T0 = 2.828×84≈237min.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.
T2∝(RE+h)3. T02 = kRE3, h = 3RE, r = 4RE. T2 = k(4RE)3 = 64kRE3. T = T064 = 90×8 = 720min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 720 min. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
