A ball is thrown horizontally at 6m/s from a height of 4.9m. What is its horizontal range? (Take g\=9.8m/s2)
Time to fall: h=12gt2⇒4.9=12×9.8×t2⇒4.9=4.9t2⇒t2=1⇒t=1s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 m as the result, so option D is correct.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations