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Ag⁺ + e⁻ → Ag . 1 mol Ag (108 g) requires 1F. Moles = (1.62/108) = 0.015 mol , Charge = 0.015 × 1 = 0.015 F .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrolytic Cells and Electrolysis and Faraday's Laws
Ag⁺ + e⁻ → Ag . 1 mol Ag (108 g) requires 1F. Moles = (108/108) = 1 mol , Charge = 1 × 96500 = 96500 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Ag⁺ + e⁻ → Ag . 1 mol Ag (108 g) requires 1F. Moles = (108/108) = 1 mol , Charge = 1 × 96500 = 96500 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
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