What is the total pressure at a depth of 3.4m in seawater (ρ\=1.03×103kg/m3) with atmospheric pressure 1.01×105Pa? (Take
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 1.03×103kg/m3, g = 9.8m/s2, h = 3.4m. P = 1.01×105+1.03×103×9.8×3.4 = 1.01×105+34319.6 = 1.353196×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.35 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.