A motor lifts a 1400kg load at 3.5m/s against 3000N friction. What is the power? (Take g\=10m/s2)
Power P=W/t=F·v per NCERT. Rate of doing work. With given force and velocity, P=Fv. Calculation yields 58 kW. Hence option A correctly represents power.
Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Work, Energy and Laws of Motion - Mixed Practice