A copper rod of length 1 m and diameter 2 mm is subjected to a tensile force. If the stress is 4 × 107 N/m2, what is the
Stress: Stress = F / A. Area: A = π r2, r = 1 × 10-3 m. A = 3.14 × (1 × 10-3)2 = 3.14 × 10-6 m2. Force: F = Stress × A = 4 × 107 × 3.14 × 10-6 = 125.6 N.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.