6 public questions tagged with this topic.
Specific heat capacity determines how much heat is needed to raise the temperature of a material. Sand has a lower specific heat capacity than water, so it heats up faster.
Ref: NCERT Class 11 Physics, Chapter 11: Thermal Properties – Calorimetry.
Water is preferred as a coolant in radiators because of its high specific heat capacity, allowing it to absorb significant heat with minimal temperature rise. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Water. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Chapter 11: Thermal Properties – Calorimetry.
Moles = 50 / 63.5 = 0.7874 mol, Δ T = 125 - 25 = 100 K, qv = nCvΔ T = 0.7874 × 22.6 × 100 = 1779.5 J = 1.78 kJ.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Heat Capacity and Calorimetry and Measurement of Enthalpy
Work done: w = -PΔ V = -2 × 0.5 × 101.325 = -101.325 J . Given q = 1200 J , Δ U = q + w = 1200 - 101.325 = 1098.68 ≈ 1098.7 J .
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: First Law of Thermodynamics and Enthalpy and Internal Energy
Using the first law: Δ U = q + w. Here, q = +500 J (heat absorbed), w = -200 J (work done by system), so Δ U = 500 - 200 = 300 J.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: First Law of Thermodynamics and Enthalpy and Internal Energy
Work done: w = -PΔ V = -3 × 0.6 × 101.325 = -181.985 J . Heat absorbed: q = 1500 J . Using the first law, Δ U = q + w = 1500 - 181.985 = 1318.0 J .
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: First Law of Thermodynamics and Enthalpy and Internal Energy
