11 public questions tagged with this topic.
Gauge pressure: Pg = ρgh. ρ = 1.06×103kg/m3, g = 9.8m/s2, h = 1.5m. Pg = 1.06×103×9.8×1.5 = 15582Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.56 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 2.7m. Pg = 13.6×103×9.8×2.7 = 359856Pa = 3.59856×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 806kg/m3, g = 10m/s2, h = 1.9m. Pg = 806×10×1.9 = 15314Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.5 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 1.06×103kg/m3, g = 10m/s2, h = 2.4m. Pg = 1.06×103×10×2.4 = 25440Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.5 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 13.6×103kg/m3, g = 10m/s2, h = 2.5m. Pg = 13.6×103×10×2.5 = 3.4×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.4 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 1.03×103kg/m3, g = 10m/s2, h = 3.5m. Pg = 1.03×103×10×3.5 = 3.605×104Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 1000kg/m3, g = 10m/s2, h = 2.9m. Pg = 1000×10×2.9 = 29000Pa = 2.9×104Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.9 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure is Pg = ρgh. ρ = 1000kg/m3, g = 10m/s2, h = 5m. Pg = 1000×10×5 = 5×104Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 1.06×103kg/m3, g = 10m/s2, h = 0.9m. Pg = 1.06×103×10×0.9 = 9540Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9540 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Gauge pressure: Pg = ρgh. ρ = 806kg/m3, g = 10m/s2, h = 4.5m. Pg = 806×10×4.5 = 36270Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Absolute pressure is the total pressure, including atmospheric pressure (P = Pa+ρgh), while gauge pressure is the excess pressure above atmospheric pressure (Pg = ρgh), as defined in the chapter.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
