A 40kg wooden plank is placed on a performer’s chest. If each femur has an area of 12cm2, what is the pressure on the fe
P = FA, F = 40×10 = 400N. Total area A = 2×12×10−4 = 2.4×10−3m2. P = 4002.4×10−3≈1.67×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.67 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.