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Gauge pressure: Pg = ρgh. ρ = 1.06×103kg/m3, g = 10m/s2, h = 0.9m. Pg = 1.06×103×10×0.9 = 9540Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9540 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 1.06×103kg/m3, g = 9.8m/s2, h = 2.8m. P = 1.01×105+1.06×103×9.8×2.8 = 1.01×105+29094.4 = 1.300944×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.30 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
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