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#average pressure

2 public questions tagged with this topic.

A 70kg person stands on two bones, each with area 16cm2. What is the average pressure on the bones? (Take g\=9.8m/s2)

Pav = FA, F = mg = 70×9.8 = 686N. Total area A = 2×16×10−4 = 3.2×10−3m2. Pav = 6863.2×10−3 = 2.14375×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.14 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

A 65kg person stands on two bones, each with area 20cm2. What is the average pressure on the bones? (Take g\=10m/s2)

Pav = FA, F = mg = 65×10 = 650N. Total area A = 2×20×10−4 = 4.0×10−3m2. Pav = 6504.0×10−3 = 1.625×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.625 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.