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Propanamide (CH₃CH₂CONH₂) loses one carbon in the Hoffmann reaction to form ethylamine (CH₃CH₂NH₂), as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions of Amines - Mixed Concept Practice
Ethylamine (CH₃CH₂NH₂) reacts with butanoyl chloride (CH₃CH₂CH₂COCl) to form N-ethylbutanamide (CH₃CH₂CH₂CONHCH₂CH₃), as per the PDF’s acylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with one mole of acetyl chloride to form acetanilide (C₆H₅NHCOCH₃), as per the PDF’s acetylation reaction.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with propanoyl chloride (CH₃CH₂COCl) to form N-phenylpropanamide (C₆H₅NHCOCH₂CH₃), as per the PDF’s acylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Ethylamine (CH₃CH₂NH₂) reacts with acetyl chloride (CH₃COCl) to form N-ethylacetamide (CH₃CONHCH₂CH₃), as per the PDF’s acetylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with acetic anhydride ((CH₃CO)₂O) to form acetanilide (C₆H₅NHCOCH₃), as per the PDF’s acetylation reaction.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
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