An aluminium rod of length 1.4m and cross-sectional area 2×10−6m2 is compressed by a force producing a stress of 3×107N/
Young's modulus: Y = StressStrain. Strain: Strain = StressY = 3×1077×1010≈4.29×10−4. Compression: ΔL = Strain×L = 4.29×10−4×1.4≈6×10−4m = 0.6mm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.6mm. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.