A 5kg particle moves with velocity v\=4i^m/s at r\=−3j^m. What is the magnitude of its angular momentum about the origin
L = r×p = |i^j^k^0−30400| = k^(0×0−(−3)×4) = 12k^kg m2/s. Magnitude = 12kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 12 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.