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Question

What is the escape speed from a planet with g\=4.9m/s2 and radius 3.2×106m?

Options

Choose one · Correct answer highlighted

Explanation

ve = 2gR. ve = 2×4.9×3.2×106 = 3.136×107. ve≈5.6×103m/s = 5.6km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.6 km/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.