Practice question
Question
What is the absolute pressure at 300m depth in seawater (ρ\=1.03×103kg/m3) with Pa\=1.01×105Pa? (Take g\=10m/s2)
Explanation
P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 1.03×103kg/m3, g = 10m/s2, h = 300m. P = 1.01×105+1.03×103×10×300 = 1.01×105+3.09×106 = 3.191×106Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.19 × 10⁶ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.