Practice question
Question
A thin ring of mass 4kg and radius 0.6m has an angular momentum of 12kg m2/s. What is its angular velocity?
Explanation
I = MR2 = 4×(0.6)2 = 1.44kg m2. ω = LI = 121.44≈8.33rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.33 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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