Practice question

A1v1 = A2v2, v1 = 2.0m/min = 0.0333m/s, A1 = 9×10−4m2. Hole area: Ah = π(0.3×10−3)2, total A2 = 45×π×9×10−8≈1.272×10−5m2. v2 = 9×10−4×0.03331.272×10−5≈2.36m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.