Practice question

Given: A0 = 1.5m2, ΔT = 120−20 = 100∘C, αl = 1.9×10−5K−1. ΔA = A0×2αlΔT = 1.5×2×1.9×10−5×100 = 0.0057m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.0057 m². This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.