Practice question
Question
A rocket accelerates vertically at 6m/s2 from rest for 4s, then its engines fail. What is the maximum height reached above the ground? (Take g\=10m/s2)
Explanation
At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=6 m/s and g=10 m/s², h=1.8 m. This matches option A (75 m). Other options do not satisfy v²=u²+2as with correct signs.
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