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Question

A hydraulic lift uses a small piston of area 0.02m2 to exert a force of 200N to lift a load with a large piston of area 0.1m2. What is the mass of the load? (Take g\=10m/s2)

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Explanation

Pascal’s law: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 200N, A1 = 0.02m2, A2 = 0.1m2. F2 = 200×0.10.02 = 200×5 = 1000N. m = F2g = 100010 = 100kg.

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