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Question

A force F\=5i^+4j^N acts at r\=−3i^−2j^m. What is the magnitude of the torque about the origin?

Options

Choose one · Correct answer highlighted

Explanation

τ = r×F = |i^j^k^−3−20540| = k^((−3)×4−(−2)×5) = k^(−12+10) = −2k^Nm. Magnitude = 2Nm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2 Nm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.