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Practice question

MCQ

Question

A copper wire of length 2 m and cross-sectional area 3 × 10-6 m2 is stretched by a force of 150 N. If the strain produced is 1 × 10-3, what is the Young's modulus of copper?

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Explanation

Young's modulus: Y = Stress / Strain. Stress: Stress = F / A = 150 / (3 × 10-6) = 5 × 107 N/m2. Strain: 1 × 10-3. So, Y = (5 × 107) / (1 × 10-3) = 5 × 1010 N/m2.

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