Practice question
Question
A 7kg block at 12m/s encounters a force F\=−2.4xN from x\=1m to x\=5m. What is the final speed?
Explanation
Initial K=12×7×122=504J. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 504 J as the result, so option A is correct.