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Question

Why does the voltage across an inductor in a series LCR circuit potentially exceed the source voltage
at resonance?

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Explanation

**Condition for resistive behavior** X_L = X_C, so ωL=1/ωC, ω²=1/LC, this is resonance, impedance purely resistive Z=R, current maximum, power maximum P= V²/R, inductive and capacitive reactances equal magnitude opposite sign cancel, circuit appears resistive. At resonance, current is maximized ( I = (V/R) ), and the voltage across the inductor ( V_L = I X_L ) can exceed the source voltage if X_L > R . This is possible because V_L and V_C are out of phase with the source voltage, and their vector sum with V_R equals the source voltage. Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L -

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