Practice question
Question
What volume of O₂ at STP is required to burn 6 g of CH₄ completely to CO₂ and H₂O? (Molar mass: CH₄ = 16 g/mol)
Explanation
Reaction: CH₄ + 2O₂ → CO₂ + 2H₂O. Moles of CH₄ = 6/16 = 0.375 mol. 1 mol CH₄ needs 2 mol O₂; 0.375 mol needs 0.75 mol. Volume = 0.75 × 22.4 = 16.8 L.
Related blogs
Guides and insights connected to this topic
Periodic Classification of Elements Notes - Dobereiner Triads, Newlands Octaves, Mendeleev and Modern Periodic Table
Explore early attempts to classify elements, covering Dobereiner’s triads, Newlands’ law of octaves and Mendeleev’s table with examples and key details.
Breathing and Exchange of Gases Biology Notes - Respiratory System, Mechanism of Breathing, Lung Volumes, Gas Transport and Regulation
Clear biology notes on breathing and gas exchange. Learn human respiratory organs, breathing mechanics, and pulmonary gas transport.
Determination of KLa
IntroductionThe volumetric liquid mass transfer coefficient (KLa) is a useful parameter to characterize the bioreactor's capacity for aerati...
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.