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Question

What volume of N₂ at STP is required to react with 6 g of H₂ to produce NH₃ with 60% yield? (Molar mass: H₂ = 2 g/mol)

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Explanation

Reaction: N₂ + 3H₂ → 2NH₃. Moles of H₂ = 3 mol. 3 mol H₂ need 1 mol N₂; actual N₂ = 1 / 0.6 ≈ 1.67 mol. Volume = 1.67 × 22.4 ≈ 37.41 L.

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