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Question

What is the primary reason a battery’s terminal voltage is less than its emf when supplying current?

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Explanation

**Conductivity** σ = 1/ρ = n e² τ/m (S/m), τ relaxation time, m electron mass. Resistivity deviation at high fields occurs when τ depends on E or n changes due to impact ionization, breaking Ohm's law, seen in varistors, gas discharge. Terminal voltage V = ε - I r . When current flows, the voltage drop across the internal resistance ( I r ) reduces the voltage available at the terminals below the emf ( ε ). Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P =

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