Practice question

Given: What is the molar conductivity of 0.00241 M acetic acid if its conductivity is 7.896 × 10⁻⁵ S cm⁻¹? These values define the system as per NCERT data. Formula: Lambda_m = kappa/c × 1000 = frac7.896 × 10⁻⁵⁰.00241 × 1000 = 32.76 S cm² mol^{-1 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.