Practice question
Question
What is the minimum speed to escape from 6 R_E from Earth’s nter? ( g = 9.8 m/s², R_E = 6.4 × 10⁶m )
Explanation
Given:
What is the minimum speed to escape from 6 R_E from Earth’s nter? ( g = 9.8 m/s², R_E = 6.4 × 10⁶m )
Formula:
v_e = √2 g R_E²/6 R_E = √2 × 9.8 × 6.4 × 10⁶/6.
Substitution & Calculation:
v_e = √2.09 × 10⁷approx 4.57 × 10³m/s approx 4.6 km/s .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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