Practice question
Question
The wavenumber of the third line in the Lyman series of a hydrogen atom is: (RH = 1.097 × 10⁷ m⁻¹)
Explanation
Lyman: n₁=1, third line n₂=4. ν̄ = RH (1 - 1/16) = 1.028×10⁷ m⁻¹.
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