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Question

The solubility of a gas in water follows Henry’s law with a constant of 150 bar. If the gas’s partial pressure decreases from 6 bar to 3 bar, by what factor does its solubility decrease?

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Explanation

Henry’s law: p = KH · x . Initial x₁ = (6/150) = 0.04 , final x₂ = (3/150) = 0.02 . Factor = (x₂/x₁) = (0.02/0.04) = 0.5 (decreases by a factor of 2).

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