Skip to content

Question

The enthalpy of vaporization of a liquid is 32.00 kJ/mol at 350 K. What is Δ U if Δ ng = 1 ? ( R = 8.314 J/mol·K )

Options

Choose one · Correct answer highlighted

Explanation

For Δ ng = 1 , RT = 8.314 × 350 × 10⁻³ = 2.9099 kJ . Using Δ H = Δ U + Δ ng RT , Δ U = 32.00 - 2.9099 = 29.09 kJ/mol .

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.