Practice question
Question
The enthalpy of vaporization of a liquid is 32.00 kJ/mol at 350 K. What is Δ U if Δ ng = 1 ? ( R = 8.314 J/mol·K )
Explanation
For Δ ng = 1 , RT = 8.314 × 350 × 10⁻³ = 2.9099 kJ . Using Δ H = Δ U + Δ ng RT , Δ U = 32.00 - 2.9099 = 29.09 kJ/mol .
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