Practice question

**Capacitance depends on geometry** not charge, C = Q/V constant for given arrangement. Parallel plate C ∝ A/d, so larger area and smaller separation increase capacitance, principle used to increase storage by using large area foils with thin dielectric. In parallel, both capacitors have the same voltage V . Capacitance is C = (K ε₀ A/d) , where K is the dielectric constant. A higher K increases C . Energy stored is U = (1/2) C V² , so a larger C (due to higher K ) leads to more energy stored for the same V . The higher K allows more charge ( Q