Practice question
Question
How many joules are equivalent to 350 cal of heat? (1 cal = 4.186 J )
Explanation
**Energy transfer** first law ΔU = Q - W, W includes P-V work, shaft work, electrical work, Q includes conduction Fourier law, convection, radiation Stefan-Boltzmann, distinction important because work is controllable, heat spontaneous from hot to cold, entropy associated with heat not work, explaining why heat engine efficiency <100%. Heat in J = Heat in cal × 4.186 . 350 × 4.186 = 1465.1 J ≈ 1465 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W = n R T ln(V₂/V₁), adiabatic P V^γ = const and η = 1 - T_c/T_h,
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