Skip to content
Login Register

Practice question

MCQ

Question

For C₂H₄(g) + H₂(g) → C₂H₆(g) , Δ H = -137.00 kJ/mol at 298 K. What is Δ U ? ( R = 8.314 J/mol·K )

Options

Choose one · Correct answer highlighted

Explanation

For Δ ng = 1 - 2 = -1 , RT = 8.314 × 298 × 10⁻³ = 2.4776 kJ . Using Δ H = Δ U + Δ ng RT , Δ U = -137.00 - (-1 × 2.4776) = -137.00 + 2.4776 = -134.52 kJ/mol .

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.

Related blogs

Guides and insights connected to this topic