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Question

For 2SO₃(g) → 2SO₂(g) + O₂(g) , Δ H = 197.80 kJ/mol at 298 K, what is Δ U ? ( R = 8.314 J/mol·K )

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Explanation

For Δ ng = 3 - 2 = 1 , RT = 8.314 × 298 × 10⁻³ = 2.4776 kJ . Using Δ H = Δ U + Δ ng RT , Δ U = 197.80 - 1 × 2.4776 = 195.32 kJ/mol .

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