Practice question
Question
An enzyme catalyzes the conversion of 30 micro M of a substrate to product at reaction velocity of 9.0microM s ⁻¹ When [Et] = 30 nM and K m = 10 micro M, Kcat/Km of enzyme will ben x 10 ⁷ M ⁻¹ s ⁻¹ The value of n is (in integer). (NAT)
Explanation
Mechanistically, enzyme kinetics involves substrate binding and catalytic efficiency determine reaction rates. This validates Option NAT because it reflects active-site specificity and regulation, a pattern repeatedly demonstrated in biochemistry research.
Discussion
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