Practice question
Question
An electron in He⁺ transitions from n = 3 to n = 1. What is the wavelength of the emitted photon in nm? (RH = 1.097 × 10⁷ m⁻¹, c = 3.0 × 10⁸ m s⁻¹)
Explanation
For He⁺ (Z=2), wavenumber ν̄ = Z² RH (1/n₁² - 1/n₂²) = 4 × 1.097×10⁷ (1/1² - 1/3²) ≈ 3.901×10⁷ m⁻¹. λ = 1/ν̄ ≈ 2.563×10⁻⁸ m = 25.63 nm.
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