Practice question
Question
A wave on a string has an amplitude of 0.03 m and a frequency of 25 Hz. What is the maximum transverse
speed of a particle?
Explanation
**Nature of wave** determines energy transfer mechanism. Longitudinal nature of sound explains propagation through fluids with density variations carrying energy, unlike transverse waves needing rigidity for restoring force. ω = 2π v = 2π × 25 = 50π rad/s . Max speed: vₘₐₓ = a ω = 0.03 × 50π ≈ 4.71 m/s . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 4.7 m/s, illustrating frequency-length-speed interdependence and quantization by boundaries.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.