Practice question
Question
A uniform rod of mass 6kg and length 3m is pivoted at one end. What is its moment of inertia about the pivot?
Explanation
For a rod pivoted at one end: I = 13ML2. M = 6kg, L = 3m. I = 13×6×(3)2 = 2×9 = 18kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 18 kg m². This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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