Practice question
Question
A series LCR circuit has \( R = 90 \, \Omega \), \( X_L = 70 \, \Omega \), \( X_C = 50 \, \Omega \).
What is the impedance?
Explanation
**Impedance behavior at high frequencies** X_L=ωL dominates ∝ f, X_C=1/ωC →0, so Z≈√(R²+X_L²)≈X_L large, current small, circuit inductive, φ→90°, at low frequencies X_C large, Z≈X_C, capacitive, φ→-90°, at intermediate resonance Z minimal =R. Z = √(R² + (X_L - X_C)²) . Z = √(90² + (70 - 50)²) = √(8100 + 400) = √(8500) ≈ 92.2 Ω . Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms = V_rms/Z, P = V_rms I_rms cosφ, V_s/V_p = N_s/N_p, calculation gives 92.2 Ω, consistent with phasor analysis and resonance condition X_L = X_C.
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