Practice question
Question
A satellite orbits a planet at 5×107m from its center with a period of 12 hours. What is the planet’s mass? (G\=6.67×10−11N m2/kg2)
Explanation
M = 4π2r3GT2. T = 12×3600 = 43200s, T2 = 1.866×109s2. r3 = (5×107)3 = 1.25×1023m3. M = 4×(3.14)2×1.25×10236.67×10−11×1.866×109. M = 4.93×10241.245×10−1≈3.96×1025kg. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.0 × 10²⁵ kg. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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