Practice question
Question
A pipe open at both ends has a length of 0.57 m and resonates with a source of frequency 900 Hz. What
is the harmonic number if the speed of sound is 342 m/s?
Explanation
**Organ pipe modes** illustrate boundary influence. Closed pipe odd harmonic series contrasts with open pipe full series, affecting timbre. Frequency scales inversely with length, explaining pitch variation with pipe length. v_n = (n v/2L) . 900 = (n × 342/2 × 0.57) = (n × 342/1.14) . 900 = n × 300 ⇒ n = (900/300) = 3 . Third harmonic. Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 3, illustrating frequency-length-speed interdependence and quantization by boundaries.
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