Practice question

Given: A physical quantity is expressed as Q = k v^a m^b t^c, where v is velocity, m is mass, t is time, and [Q] = [M L T^{-1] . Find a, b, c . These values define the system as per NCERT data. Formula: [v] = [L T^{-1], [m] = [M], [t] = [T]. This is standard NCERT relation. Substitution & Calculation: [Q] = [L T^{-1]^a [M]^b [T]^c = [M^b L^a T^{-a+c] . Equate: b = 1, a = 1, -a + c = -1 . -1 + c = -1 Rightarrow c = 0 . a = 1, b = 1, c = 0 . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.