Practice question

Given: A pendulum of length 0.49 m oscillates with g = 9.8 m/s² . What is its frequency? Formula: Period: T = 2π √L/g = 2π √0.49/9.8 = 2π √0.05 approx 1.404 s. Substitution & Calculation: Frequency: v = 1/T = 1/1.404 approx 0.712 Hz . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.