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Question

A mass of \( 4 \, \text{kg} \) is attached to a spring with \( k = 1600 \, \text{N/m} \) and displaced
by \( 5 \, \text{cm} \). What is the total energy?

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Explanation

**Damped oscillations** occur when resistive forces dissipate energy, amplitude decays exponentially as A(t) = A₀ e^(-b t/2m), b damping coefficient (kg/s), frequency slightly reduced ω' = √(ω₀² - (b/2m)²). Damping arises from friction or viscosity, energy loss per cycle proportional to velocity squared, motion eventually stops. Total energy: E = (1/2) k A² . A = 0.05 m, k = 1600 N/m . E = 0.5 × 1600 × (0.05)² = 0.5 × 1600 × 0.0025 = 2 J . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 2.0 J

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